Skip to content
View in the app

A better way to browse. Learn more.

TEST SITE

A full-screen app on your home screen with push notifications, badges and more.

To install this app on iOS and iPadOS
  1. Tap the Share icon in Safari
  2. Scroll the menu and tap Add to Home Screen.
  3. Tap Add in the top-right corner.
To install this app on Android
  1. Tap the 3-dot menu (⋮) in the top-right corner of the browser.
  2. Tap Add to Home screen or Install app.
  3. Confirm by tapping Install.

Standing Waves

When you send a signal down a transmission line and the load at the far end perfectly absorbs it, the signal simply travels from source to load with no reflections. But this perfect match is the exception, not the rule. When any mismatch exists between the line's characteristic impedance and the load — an unterminated logic input, a 75-ohm monitor on a 50-ohm cable, a connector with the wrong impedance — a portion of the signal is reflected back toward the source. For a continuous sine wave, that reflected wave combines with the incident (forward) wave to create a pattern of voltage and current that does not travel: it stands in place. These are standing waves, and they are the physical reality that the voltage standing wave ratio (VSWR) describes. For a digital signal, the same reflections show up as overshoot and ringing on every edge.

What you will learn: How reflected waves arise, how incident and reflected waves combine to form standing waves, the voltage and current patterns along a mismatched line, what determines the size of the standing wave pattern (VSWR), the special cases of open-circuit, short-circuit and matched loads, and how the same reflections appear as overshoot and ringing on a digital signal.
Diagram of a transmission line showing the voltage standing wave pattern (sinusoidal envelope with maxima at voltage antinodes and minima at voltage nodes) and the current standing wave pattern (sinusoidal envelope 90 degrees offset from voltage, with current maxima where voltage minima occur and vice versa), with the load at the right end and source at the left

Voltage and current standing wave patterns on a mismatched transmission line. Note that current maxima coincide with voltage minima and vice versa — they are exactly 90° out of phase along the line.

View Larger

What Standing Waves Are

The word "standing" is key — unlike a traveling wave, which moves along the line in one direction, a standing wave appears stationary. If you could take an instantaneous snapshot of the voltage at every point on a mismatched transmission line and plot it, you would see a sinusoidal pattern with fixed maxima and minima at specific positions along the line. Those positions do not move as time passes — they stand in place.

A standing wave is actually the superposition (sum) of two traveling waves: the incident wave moving toward the load and the reflected wave moving back toward the source. At any given point along the line, these two waves add together. Sometimes they add constructively (at voltage antinodes), producing voltage levels higher than either wave alone. Sometimes they add destructively (at voltage nodes), producing voltage levels lower than either wave.

The analogy of a guitar string is instructive. When you pluck a guitar string, the wave energy bounces off the fixed ends (analogous to mismatched loads) and the forward and backward waves combine to form standing modes — the vibrating patterns you see on a guitar string. The fixed points that do not move are nodes; the points of maximum vibration are antinodes. A transmission line with reflections behaves exactly the same way, just at much higher frequencies.

How Standing Waves Form

Consider a transmission line of characteristic impedance Z₀ = 50 ohms terminated in a load ZL = 100 ohms (a 2:1 impedance mismatch). The incident wave travels toward the load with a voltage amplitude Vi and current amplitude Ii = Vi/50.

When this wave reaches the load, it cannot simply be absorbed because the load's impedance ratio V/I is 100 ohms, not 50 ohms. Kirchhoff's voltage and current laws must be satisfied at the load terminals — the voltage and current must be continuous. The only way to satisfy these boundary conditions is for a reflected wave to be generated. The reflected wave travels back toward the source with an amplitude determined by how severe the mismatch is.

The fraction of the incident voltage that is reflected is given by the voltage reflection coefficient Γ (gamma):

Voltage reflection coefficient: Γ = (ZL − Z₀) / (ZL + Z₀)
  • Γ = reflection coefficient (complex in general, real for purely resistive loads)
  • ZL = load impedance
  • Z₀ = characteristic impedance of the line
  • |Γ| = 0 means no reflection (perfect match)
  • |Γ| = 1 means total reflection (open or short circuit)
Example: 50-ohm line, 100-ohm resistive load:

Γ = (100 − 50) / (100 + 50) = 50/150 = +0.333

The reflected voltage amplitude is 33.3% of the incident voltage. The sign is positive, meaning the reflected wave has the same polarity as the incident wave at the load.

Example: 50-ohm line, 25-ohm resistive load:

Γ = (25 − 50) / (25 + 50) = −25/75 = −0.333

The reflected voltage is still 33.3% of the incident voltage, but now it has opposite polarity at the load (negative sign). This is the origin of the "polarity inversion" when a wave reflects from a load lower than the line impedance.

Once the reflected wave is created at the load, it travels back toward the source. The source has its own output impedance, and if the source is not matched to the line, a portion of the reflected wave will be re-reflected from the source toward the load again. A signal generator or a well-designed RF amplifier has an output impedance close to 50 ohms, so most of the returning wave is absorbed and not re-reflected. A logic gate, by contrast, has a low output impedance (typically 10–40 ohms), so the returning wave is re-reflected with inverted polarity — and the signal bounces back and forth along the line several times before it settles. That is the origin of ringing on unterminated digital lines.

Voltage and Current Patterns

At any point along the mismatched line, the total voltage is the sum of the incident and reflected voltage waves, and the total current is the sum of incident and reflected current waves. Because the two waves are traveling in opposite directions, the phase relationship between them changes continuously along the line.

The result is that the RMS (time-averaged) voltage and current magnitudes follow a sinusoidal pattern along the line:

  • Voltage maximum (antinode): where incident and reflected voltage waves add constructively. Here |V| = |Vi| + |Vr|.
  • Voltage minimum (node): where they add destructively. Here |V| = |Vi| − |Vr|.
  • Current maximum (antinode): where current waves add constructively. This is always at the same location as the voltage minimum.
  • Current minimum (node): always at the same location as the voltage maximum.

This 90° offset between voltage and current standing wave patterns is a fundamental feature of lossless transmission lines. Where the voltage is highest, the current is lowest, and vice versa — exactly the relationship you would expect from an impedance perspective (high V/I = high impedance; low V/I = low impedance).

The positions of the voltage maxima and minima are fixed in space (that is what makes them "standing"), but they depend on the position of the load and the frequency. Change the frequency or change the load, and the positions shift.

Special Cases: Short, Open, and Matched Loads

Three special termination conditions produce the most extreme and instructive standing wave patterns:

Short-circuit termination (ZL = 0)

Γ = (0 − Z₀)/(0 + Z₀) = −1. The reflection coefficient is −1: total reflection with polarity inversion. The voltage at the short is zero (because a short circuit forces V = 0). The current at the short is maximum (because all the incident wave current adds to the reflected wave current). Moving quarter-wavelength back from the short, the situation reverses: voltage is maximum, current is minimum. The standing wave pattern has voltage null at the load and maxima every half-wavelength back.

This explains why a short-circuit stub, exactly quarter-wave long, presents an open circuit (maximum impedance, zero current) at its input — the current minimum corresponding to the voltage maximum at a quarter-wave from the short.

Open-circuit termination (ZL = ∞)

Γ = (∞ − Z₀)/(∞ + Z₀) = +1. Total reflection without polarity inversion. The voltage at the open is maximum (the reflected voltage adds to the incident voltage with the same polarity). The current at the open is zero (no current can flow through an open circuit). A quarter-wavelength back from the open, the situation reverses: voltage minimum, current maximum. An open-circuit stub, quarter-wave long, presents a short circuit at its input.

Matched termination (ZL = Z₀)

Γ = 0. No reflection at all. The voltage and current are constant (no variation) along the entire line — the pattern is flat. This is the ideal condition for a transmission line: all the incident power is absorbed by the load, nothing returns. The VSWR is 1:1.

Three-panel diagram showing how standing waves form: top panel shows the incident wave traveling right, middle panel shows the reflected wave traveling left (same amplitude but opposite direction), bottom panel shows the superposition of both waves forming a standing wave pattern with fixed nodes and antinodes, with the mismatched load at the right end

Standing waves form from the superposition of an incident wave (traveling right) and a reflected wave (traveling left). The sum creates a stationary pattern of maxima and minima whose positions depend on the load impedance and frequency.

View Larger

What VSWR Measures

The voltage standing wave ratio (VSWR) is the ratio of the maximum voltage amplitude to the minimum voltage amplitude along the line:

VSWR = Vmax / Vmin = (1 + |Γ|) / (1 − |Γ|)
  • VSWR ranges from 1:1 (matched, no reflections) to ∞:1 (total reflection)
  • For a matched load: |Γ| = 0, VSWR = (1+0)/(1−0) = 1
  • For a 2:1 impedance mismatch (ZL = 2Z₀ or Z₀/2): |Γ| = 1/3, VSWR = (1+1/3)/(1−1/3) = 4/3 ÷ 2/3 = 2
  • For a short or open circuit: |Γ| = 1, VSWR = ∞

VSWR gives you a single number that characterizes the severity of the mismatch. Datasheets for cables, connectors, attenuators and RF modules quote it as a measure of quality: a good SMA connector or 50-ohm terminator might be specified at better than 1.1:1, a typical RF amplifier input at better than 2:1. Numbers like 10:1 or ∞ indicate an open, a short or a serious fault.

VSWR is also related to reflected power through the reflection coefficient:

Reflected power = |Γ|² × incident power = ((VSWR − 1)/(VSWR + 1))² × incident power

At VSWR 2:1: |Γ| = 1/3, reflected power = 1/9 = 11.1% of incident power

At VSWR 3:1: |Γ| = 1/2, reflected power = 1/4 = 25% of incident power

These calculations are developed in full detail in the next lesson, together with return loss, the form most network analyzers display.

Nodes, Antinodes, and Half-Wave Periodicity

The standing wave pattern along a transmission line repeats every half-wavelength. If you have a voltage maximum at some point on the line, the next voltage maximum is exactly half a wavelength farther toward the source. Voltage minima are also spaced a half-wavelength apart. Voltage maxima and minima are spaced a quarter-wavelength apart from each other.

This half-wavelength periodicity is why VSWR does not depend on where along a lossless line you measure it — the ratio Vmax/Vmin is the same everywhere along the line.

On a real cable with loss, the measured VSWR improves as you move away from the load toward the source. This is because the lossy line attenuates the reflected wave on its way back as well as the incident wave on its way out, so the reflection looks smaller from the source end. A long, lossy cable can make a badly mismatched load look almost matched — which is why precise measurements are made at the end of a short, low-loss cable, or the analyzer is calibrated right at the point of measurement.

Reflections in the Time Domain

Standing waves describe a steady sine wave. Digital signals are steps, and it is often clearer to follow each step as it travels and reflects. The reflection coefficients at both ends of the line tell you everything:

Γload = (ZL − Z₀) / (ZL + Z₀)    Γsource = (ZS − Z₀) / (ZS + Z₀)

The step launched into the line is Vlaunch = VS × Z₀ / (ZS + Z₀). Each time a wave reaches an end, it is multiplied by that end's Γ and sent back the other way.

Worked example — an unterminated 50-ohm trace driven by a 3.3 V logic output:

Driver output impedance ZS = 20 Ω; trace Z₀ = 50 Ω; the far end is a CMOS input (effectively open, Γload = +1). One-way delay T.

Launched step: 3.3 × 50 / (20 + 50) = 2.36 V. Γsource = (20 − 50) / 70 = −0.43.

At time T the step reaches the open end and reflects with Γ = +1: the far end jumps to 2.36 + 2.36 = 4.71 V — 43% above the 3.3 V supply.

At 2T the 2.36 V reflection reaches the driver and is re-reflected as 2.36 × (−0.43) = −1.01 V.

At 3T that wave reaches the far end and doubles again: the far end falls to 4.71 − 2.02 = 2.69 V.

At 5T it rises again by 2 × 0.43 × 1.01 = 0.87 V to 3.56 V, and so on, ringing around 3.3 V and settling after several round trips.

The overshoot to 4.71 V exceeds the input's absolute maximum rating and forces current through its protection diodes; if the ringing dipped below the logic threshold, the receiver would see a false edge. Adding a 30 Ω series resistor at the driver (so ZS = 50 Ω and Γsource = 0) absorbs the first reflection and the far end steps cleanly to 3.3 V — the series termination covered in the Termination lesson.

A time-domain reflectometer (TDR) uses exactly this behavior in reverse: it launches a fast step and watches the reflections return. A step up in the reflected waveform means a higher impedance (an open, a narrow trace, a loose connector); a step down means a lower impedance (a short, a wide trace, a crushed cable). The delay to each step gives its position along the line.

Practical Consequences of Standing Waves

Understanding standing waves and reflections reveals several important practical points:

High voltage at voltage antinodes

At a voltage antinode, the voltage on the line is Vmax = Vi(1 + |Γ|). At VSWR 5:1, this is 1.67 × Vi — the peak voltage is two-thirds higher than the incident wave amplitude. In an RF power system this can stress connectors and cause breakdown; on a digital line, the same effect is the overshoot that drives inputs beyond their supply rail.

High current at current antinodes

At a current antinode, the current in the conductor is Imax = Ii(1 + |Γ|). Higher current means more I²R resistive heating at that point. If the current antinode falls at a connector or a damaged section of cable in a high-power system, the concentrated heating can damage that component.

Where the reflected energy goes

Standing waves are a symptom of a mismatch — and the mismatch itself does not directly destroy power. The reflected power does not simply disappear; it travels back to the source. A matched source (a signal generator, a 50-ohm amplifier output) absorbs it as heat. An RF power amplifier driving a badly mismatched load may have to absorb a large fraction of its own output, which is why such amplifiers include protection circuits that reduce their output when the reflected power is high. A low-impedance logic driver re-reflects it, producing ringing.

A perfect match does not mean the circuit works

A low VSWR reading only tells you that the load impedance matches the line. A 50-ohm resistor gives a perfect 1:1 VSWR, and so does a broken amplifier whose input happens to look like 50 ohms. Whether the load is doing its job — amplifying, measuring, receiving — is a separate question entirely.

Frequently Asked Questions

Do standing waves destroy power?

Standing waves themselves do not directly destroy power — they are just a description of the voltage and current distribution on the line. What causes power loss is the increased I²R heating in the cable conductors when the current is elevated by standing waves (at current antinodes). On a well-matched, low-loss cable, the additional loss is small. On a long, high-loss cable, additional loss from standing waves can be substantial. The reflected power itself is not destroyed; it travels back to the source, where a matched source absorbs it, a protected RF amplifier reduces its output, or a low-impedance driver reflects it back again.

Why does the VSWR of my circuit change with frequency?

Because the load impedance varies with frequency. A chip input that looks like 50 ohms at low frequencies has some capacitance that lowers its impedance as frequency rises; an RF module matched at its design frequency drifts off match on either side; a filter is deliberately matched only in its passband. Additionally, as you change frequency, the electrical length of the cable changes, which rotates the load impedance as seen from the source end. Both effects make the VSWR change with frequency even without any physical change to the circuit. To know the true load impedance, measure at the load (or calibrate the analyzer to remove the cable) — all the cable does is transform and rotate whatever impedance the load presents.

If the VSWR is 1:1, does that mean everything is working?

A 1:1 VSWR means the load (plus any cable and matching network) presents exactly the line impedance to the source. It does not tell you whether the load is doing anything useful. A 50-ohm terminator gives a perfect 1:1 VSWR and simply turns all the power into heat. A faulty amplifier, an attenuator set to the wrong value, or a filter tuned to the wrong frequency can all present a good match while doing the wrong thing. A good match gets the signal into the load; whether the load works is a separate measurement.

Do standing waves travel at the speed of light?

The standing wave pattern itself does not travel — that is what defines it as a standing wave. The individual component waves (incident and reflected) travel at the propagation velocity of the cable (c × VF). The standing wave pattern is fixed in position and simply oscillates in amplitude at the signal frequency. However, the pattern does shift position if you change the frequency — because the wavelength changes, the positions of the nodes and antinodes shift. Also note that if you abruptly change the source or the load (for example, by switching the signal on), the new steady-state standing wave pattern establishes itself at the propagation speed of the cable — it takes a few round trips for the new pattern to fully develop, which is exactly the settling you see as ringing on a digital edge.

Test Your Knowledge

Answer the questions below to check your understanding of this lesson. Every answer can be found in the lesson above.

Loading questions...

Account

Navigation

Search

Search

Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.